First a bit of background. In high school, one of our assistant coaches was a match teacher at my school. My mathematical prowess (I know, wtf does that mean, what a dork, etc etc) was somewhat well known on campus, and he would start giving me math puzzles off and on just because he knew I enjoyed the challenge. I figured all of them out, but I could not figure this one out and after a few days, he eventually told me the answer. It is very difficult IMO, and I think it will be pretty hard to google as well. If you have heard it or if you have master google skills and can find the answer online somewhere, please refrain from answering.
Ok, now the puzzle. There is a square room that is 15 x 15 x 15 feet. There is an on one of the walls, there is an ant (or any insect that can't fly or shoot a web) who we will call Ant #1, directly in the middle of the wall, 2 feet up from the floor. So the ant is 7.5 feet in and 2 feet up from the floor, in case the "directly in the middle of the wall" verbiage was confusing. On side of the wall directly opposite of the wall that ant #1 is on, there is another ant (Ant #2 obv) who is directly in the middle of the wall, but 2 feet down from the ceiling. Assuming that Ant #2 is paralyzed and cannot move at all, what is shortest way (in terms of distance) for Ant #1 to reach Ant #2? And no, 30 feet is obviously not the answer.