Here is how to get the answer. It doesn't work for a perfectly square room.
http://puzzle.dse.nl/math/sneaking_spider_us.html
Here is how to get the answer. It doesn't work for a perfectly square room.
http://puzzle.dse.nl/math/sneaking_spider_us.html
I will smash your face into a car windshield and then take your mother, Dorothy Mantooth, out to a nice seafood dinner and never call her again!
Tell me about it, this morning, I woke up and I shit a squirrel, but what I can't get is the damn thing is still alive. So now, I've got a shit covered squirrel running around my office and I don't know what to name it.
c = square root of A squared + B squared
c = square root of 19 squared + 30 squared
c = square root of 361 + 900
c = sqaure root of 1261
c = 35.51 feet
direct route up the wall across the ceiling and down is
13 + 15 + 2 = 30 feet
The problem only works for a rectangle.
I am changing my answer to 18.601. It asks for the shortest possible distance, and never actually says that all wall space must be covered so the ants are 11 ft away in heighth and 15 feet apart. 11 squared plus 15 squared is 356 and the square root of that is 18.601. I think it's called somethin like the pythagorean theorem.
Curtis Chenoweth
wannabe national champ headed to a new home:walkman:
Well this is irritating enough. The opening intructions say that the ant can't walk "on air".
If you label ant #2 as point #2 on wall B, ant #1 as point #1 on wall A, the "floor or ceiling" as wall C, and either of the other two sides as Wall D,
and
you wish to move from point #1 to point # 2 by shortest possible route while, at all times, on a wall surface,
then
tranversing either wall c or d, or a corner connecting those two walls will be required,
and,
that required distance is, at a minimum, 15 feet.
In other words, the shortest possible distance to traverse from wall A to wall B is fifteen feet. Nothing shorter is possible. So 15 feet is part of the answer.
The remaining tasks would be to determine distance on wall A and distance on wall B. It sure seems the sum of those distances can be no smaller than another 15 feet. Any attempt to move other than parallel or perpindicular to the lines that circumscribe the walls seems to add distance.
If it were part of the requirement that some non-parallel movement must be made, then I think the smallest answer could be 31.95 feet.
Is this a trick question?
If not, I want to see given the distance transversed on each wall when the answer is given.
Aw hell. Now I'm questioning my own assumptions. One, that the sum of distance transversed on Wall A and B has to be at least 15. That's not true.
Now I have to figure if that makes a difference. Same with my assumption that either wall C or D must be transversed but not both.
I don't think it will, but....
The other two possible answers are 35.51 and 33.54.
I will smash your face into a car windshield and then take your mother, Dorothy Mantooth, out to a nice seafood dinner and never call her again!
Tell me about it, this morning, I woke up and I shit a squirrel, but what I can't get is the damn thing is still alive. So now, I've got a shit covered squirrel running around my office and I don't know what to name it.
Any number of answers are possible, especially if the ant is "drunk" (can't walk a straight line).
I give up.