Discuss Tough math puzzle at the Non Wrestling Talk within the Wrestling Talk Forums; Here is how to get the answer. It doesn't work for a perfectly square room. ...
1. ## Re: Tough math puzzle

Here is how to get the answer. It doesn't work for a perfectly square room.

http://puzzle.dse.nl/math/sneaking_spider_us.html

2. ## Re: Tough math puzzle

Originally Posted by homerdindon
So much for not responding if you have master google skills.
I found the mathematical solution. It doesn't work the same on a cube. The route is actually longer, 35.5 feet than the direct route - 30 feet. Now I figure these are the rare Mexican Jumping Ants that can leap 18.6 feet wall to wall.

3. ## Re: Tough math puzzle

c = square root of A squared + B squared
c = square root of 19 squared + 30 squared
c = square root of 361 + 900
c = sqaure root of 1261
c = 35.51 feet
direct route up the wall across the ceiling and down is
13 + 15 + 2 = 30 feet

The problem only works for a rectangle.

4. ## Re: Tough math puzzle

I am changing my answer to 18.601. It asks for the shortest possible distance, and never actually says that all wall space must be covered so the ants are 11 ft away in heighth and 15 feet apart. 11 squared plus 15 squared is 356 and the square root of that is 18.601. I think it's called somethin like the pythagorean theorem.

5. ## Re: Tough math puzzle

Originally Posted by The Big Stiffy
I am changing my answer to 18.601. It asks for the shortest possible distance, and never actually says that all wall space must be covered so the ants are 11 ft away in heighth and 15 feet apart. 11 squared plus 15 squared is 356 and the square root of that is 18.601. I think it's called somethin like the pythagorean theorem.
Yes sir, the Mexican Jumping Ants theory.

6. ## Re: Tough math puzzle

Well this is irritating enough. The opening intructions say that the ant can't walk "on air".

If you label ant #2 as point #2 on wall B, ant #1 as point #1 on wall A, the "floor or ceiling" as wall C, and either of the other two sides as Wall D,

and

you wish to move from point #1 to point # 2 by shortest possible route while, at all times, on a wall surface,

then

tranversing either wall c or d, or a corner connecting those two walls will be required,

and,

that required distance is, at a minimum, 15 feet.

In other words, the shortest possible distance to traverse from wall A to wall B is fifteen feet. Nothing shorter is possible. So 15 feet is part of the answer.

The remaining tasks would be to determine distance on wall A and distance on wall B. It sure seems the sum of those distances can be no smaller than another 15 feet. Any attempt to move other than parallel or perpindicular to the lines that circumscribe the walls seems to add distance.

If it were part of the requirement that some non-parallel movement must be made, then I think the smallest answer could be 31.95 feet.

Is this a trick question?

If not, I want to see given the distance transversed on each wall when the answer is given.

7. ## Re: Tough math puzzle

Aw hell. Now I'm questioning my own assumptions. One, that the sum of distance transversed on Wall A and B has to be at least 15. That's not true.
Now I have to figure if that makes a difference. Same with my assumption that either wall C or D must be transversed but not both.

I don't think it will, but....

8. ## Re: Tough math puzzle

The other two possible answers are 35.51 and 33.54.

9. ## Re: Tough math puzzle

Any number of answers are possible, especially if the ant is "drunk" (can't walk a straight line).

I give up.

Page 3 of 4 First 1234 Last